What is the pressure if 3 mol of gas has a volume of 2.3 L at 15°C?

30.84atm

Explanation:

Using the ideal gas formula:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821Latm/molK)

T = temperature (K)

According to the provided information in this question,

P = ?

V = 2.3 L

n = 3 mol

T = 15°C = 15 + 273 = 288K

Using PV= nRT

P = nRT/V

P = (3 × 0.0821 × 288) ÷ 2.3

P = 70.9344 ÷ 2.3

P = 30.84atm

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