The decomposition of potassium chlorate, KClO3, is used as a source of oxygen in labs. How many moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas?

Reaction takes place is

2KClO3 --> 2KCl + 3O2

from above equation 2 moles of potassium chlorate is forming 3 moles of Oxygen gas.

now given 6.83 moles of oxygen and moles of potassium chlorate is missing,

consider x moles of potassium chlorate are needed to form 6.83 moles of oxygen

from above condition, .

3 》》》》2

x 》》》》6.83

3/x = 2/6.83

x = 3×6.83/2

x= 10.245

Answer- 10.245 moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas.

a graduated cylinder.

explanation:

"the periodic table is arranged in order of atomic number."