A change in pressure does not affect equilibrium in the above reaction. Which of the following is the best explanation for this? *
The mass on both sides of the reaction are equal
The number of moles/molecules on both sides of the reaction are equal
all three are gases and not affected by pressure
Use the equation below to answer the following questions.
H2(g) +F2(g) → → 2HF(g)

answer; talc and gypsum;

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.