Chemistry, 13.05.2021 22:30, danielcano1228

Lead (II) Sulfate reacts with sodium iodide in a double displacement reaction. Write out the reaction and balance. There are 18 moles of lead sulfate available and 35 moles of sodium iodide. Answer all of the following: A) Which is the limiting reactant? B) Which is the excess reactant? C) How many moles of excess reactant is left over? D) How many moles of each product can be made?

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Lead (II) Sulfate reacts with sodium iodide in a double displacement reaction. Write out the reactio...