A solution was prepared by dissolving 27.1g of sucrose (C12H22O11) in 250 g of water. Find the molality of the solution(molar mass of C12H22O11 is 342.8) -.108 m
-108 m
-317 m
-.317 m

M = 0.317 m

Explanation:

From the given information:

Using the following formula:, the molality M is:

where;

M = molality

= mass of the solute = 27.1 g

= molar mass of the solute = 342.8

= mass of the given solvent  = 250 g

∴

M = 0.317 m

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons