Answer is C Carbon filtering is commonly used for water purification and this is because the activated charcoal (carbon) has been treated with
oxygen to open up millions of tiny pores between the carbon atoms. Both diamond and charcoal are made of carbon. However,
activated charcoal carbon filters are most effective at removing chlorine, sediment, taste and odor from water whereas diamond is
not. Why?
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A)
The carbon atoms in activated charcoal have a different attraction than the
carbon atoms in diamond. They are capable of attracting impurities that
diamond cannot
B)
The unusual formation of activated charcoal gives it the ability to capture
chemical through electrostatic attraction. The carbon atoms in diamond are
too far apart and will not trap other chemicals,
The huge surface area of activated charcoal gives it countless bonding
sites. When certain chemicals pass next to the carbon surface, they attach
to the surface and are trapped. The carbon atoms in diamond are not

What are the major products produced in the combustion of c10h22 under the following conditions? write balanced chemical equations for each. a. an excess of oxygen b. a slightly limited oxygen supply c. a very limited supply of oxygen d. the compound is burned in air

Since the gas in your graduated cylinder is a mixture of butane and water vapor, you must determine the partial pressure of the butane, pbutane, alone. to do this, consult a reference and record the partial pressure of the water vapor, pwater, at the temperature you recorded. use the following formula to compute the partial pressure of the butane. pbutane = atmosphere - pwater use the following combined gas law formula and compute the volume that the butane sample will occupy at stp. (hint: convert both temperatures to kelvin.) pbutane x voriginal = pstandard x vfinal troom tstandard use the following ratio and proportion formula to determine the mass of butane needed to occupy a volume of 22.4 l at stp. grams of butane you used “x” grams of butane ml of butane corrected to stp = 22,400 ml compute the theoretical molar mass of butane based on its formula and the atomic masses on the periodic table. compare your experimental results from #3 to the theoretical value of #4, computing a percent error of your findings using this formula: % error = measured value - accepted value x 100 accepted value use the following ratio and proportion formula to determine the mass of butane needed to occupy a volume of 22.4 l at stp. need asap

How do you convert 4 mmol of bromobenzene to ml?