2. If a gas at 500 mL has a temperature of 45°C, then what is the new volume when the temperature is increased to 65°C? Show your work.

531.45 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 500 mL

Initial temperature (T₁) = 45 °C

Final temperature (T₂) = 65 °C

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 45 °C

Initial temperature (T₁) = 45 °C + 273

Initial temperature (T₁) = 318 K

Final temperature (T₂) = 65 °C

Final temperature (T₂) = 65 °C + 273

Final temperature (T₂) = 338 K

Finally, we shall determine the final volume of the gas. This can be obtained as follow:

Initial volume (V₁) = 500 mL

Initial temperature (T₁) = 318 K

Final temperature (T₂) = 338 K

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

500 / 318 = V₂ / 338

Cross multiply

318 × V₂ = 500 × 338

318 × V₂ = 169000

Divide both side by 318

V₂ = 169000 / 318

V₂ = 531.45 mL

Therefore, the new volume of the gas is 531.45 mL

idk i’m struggling too

where are the choice options?