Carbon-14 has a half-life of 5730 years. How much of a 144 g sample of carbon-14 will remain after 100,000 years?

0.001 g

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 5730 years

Original amount (N₀) = 144 g

Time (t) = 100,000 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 5730 years

Time (t) = 100,000 years

Number of half-lives (n) =?

n = t / t½

n = 100,000 / 5730

n ≈ 17

Finally, we shall determine the amount remaining. This can be obtained as follow:

Original amount (N₀) = 144 g

Number of half-lives (n) = 17

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2¹⁷ × 144

N = 1/131072 × 144

N = 0.000007 × 144

N ≈ 0.001 g

Thus, the amount remaining after 100000 years is 0.001 g

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.