15.La voiture devant cet hôtel .Single choice.
s'arrête
t'arrêtes
m'arrête<...
![Chemistry](/tpl/images/cats/himiya.png)
Chemistry, 09.05.2021 08:50, lovecats12
15.La voiture devant cet hôtel .Single choice.
s'arrête
t'arrêtes
m'arrête
16.Ils quelqu'un dans la rue. Single choice.
vois
voyez
voient
17.L'enfant ses parents. Single choice.
obéit
obéie
obéis
18.Est-ce que tu le nom de cette fille?Single choice.
connais
connaît
connaiss
![answer](/tpl/images/cats/otvet.png)
Answers: 2
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Chemistry, 22.06.2019 08:30, vanessadaniellet21
Since the gas in your graduated cylinder is a mixture of butane and water vapor, you must determine the partial pressure of the butane, pbutane, alone. to do this, consult a reference and record the partial pressure of the water vapor, pwater, at the temperature you recorded. use the following formula to compute the partial pressure of the butane. pbutane = atmosphere - pwater use the following combined gas law formula and compute the volume that the butane sample will occupy at stp. (hint: convert both temperatures to kelvin.) pbutane x voriginal = pstandard x vfinal troom tstandard use the following ratio and proportion formula to determine the mass of butane needed to occupy a volume of 22.4 l at stp. grams of butane you used “x” grams of butane ml of butane corrected to stp = 22,400 ml compute the theoretical molar mass of butane based on its formula and the atomic masses on the periodic table. compare your experimental results from #3 to the theoretical value of #4, computing a percent error of your findings using this formula: % error = measured value - accepted value x 100 accepted value use the following ratio and proportion formula to determine the mass of butane needed to occupy a volume of 22.4 l at stp. need asap
Answers: 1
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Chemistry, 22.06.2019 12:20, sindy35111
Consider the reaction of a(g) + b(g) + c(g) => d(g) for which the following data were obtained: experiment initial [a], mol/l initial [b], mol/l initial [c], mol/l initial rate, mol/l. s 1 0.0500 0.0500 0.0100 6.25 x 10^-3 2 0.100 0.0500 0.0100 2.50 x 10^-2 3 0.100 0.100 0.0100 1.00 x 10^-1 4 0.0500 0.0500 0.0200 6.25 x 10^-3 what is the rate law for the reaction?
Answers: 3
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