A.) Consider the combustion of hydrogen to make water. If you start with 2.47 grams of H2 and 12.02 grams of O2, what is the limiting reactant and the theoretical yield of water? b.) The balanced chemical equations below represents the burning of carbon monoxide in oxygen to form carbon dioxide. If you have 1.000 g each of CO and O2, determine the limiting reactant and the theoretical yield in grams.

2CO(g) + O2(g) → 2CO2(g)

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.