How many moles of HCl do you need to create a 3M HCl solution, using 1.25 L of water?

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Explanation:

im not fully sure

Explanation: By the way, 37% is commercial concentrated hydrochloric acid? In this ... Add 0.205 mL of your stock solution to 100 mL deionized water. ... Yes. you are right and we may have to take 2.5g of solution and dilute to 1000ml should be ... If you have a 0.025 mole of HCl solution, so, There are 0.025 mol of HCl in 2.09 ml of HCl.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

answer: mercury

explanation: