What is the energy required to evaporate two moles of liquid water given the following equations? 2H2(g) + O2(g) → 2H2O(g) ∆H = -483.6 kJ

2H2(g) + O2(g) → 2H2O(l) ∆H = -571.6 kJ

a
44.0 kJ
b
88.0 kJ
c
527.6 kJ
d
1055.2 kJ

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answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol