Consider the following equations. N2O4 (g) <= > 2NO2(g) ΔH = + 92 KJ What happens to the shifts with the changes below 1.[N2O4] is increased = 2.[NO2] is increased = 3.Temp is increased = 4.[N2O4] is decreased = 5.[NO2] is decreased =

particle   p is an electron and particle q is a neutron

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2