The scenes below depict the relative concentrations of h3po4, h2po4โ , and hpo42โ during a titration with aqueous naoh, but they are out of order. (phosphate groups are purple, hydrogens are blue, and na+ ions and water molecules are not shown.) (a) list the scenes in the correct order. first last (b) what is the ph in the correctly ordered second scene (ka1 = 7.2 ร 10โ3, ka2 = 6.3 ร 10โ8)? ph = (c) if it requires 28.00 ml of the naoh solution to reach this scene, how much more is needed to reach the last scene? ml naoh
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Chemistry, 22.06.2019 23:00, ceejay8005
The data below were determined for the reaction shown below. s2o82โ + 3i โ (aq) โ 2so42โ + i3โ expt. # [s2o82โ] (m) [i โ] (m) initial rate 1 0.038 0.060 1.4 ร 10 โ 5 m/s 2 0.076 0.060 2.8 ร 10 โ 5 m/s 3 0.076 0.030 1.4 ร 10 โ 5 m/s the rate law for this reaction must be:
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The scenes below depict the relative concentrations of h3po4, h2po4โ , and hpo42โ during a titration...
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