What would you do to balance this reaction? IN
+ H2
=> NH3
A. Double the coefficient of N, (2 N.)
B. Multiply coefficient of H, by 3 (3 H.)
C. Multiply subscripts of H. by 3 ( H.).
D. Double the subscripts for NHą (N_H)
E. Double the coefficient of NH, [2NH:)

b) mutualism

hope this : )

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consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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