Chemistry, 01.05.2021 20:50, kristen0517

200.0 mL of 0.150 M AlCl3 is added to 200.0 mL 0.250 M BaCl2, calculate the [Ba2+], [Al3+] and the [Cl-] immediately after mixing the two solutions. Please include steps of how to do this. If possible please do on a piece of paper and upload image

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200.0 mL of 0.150 M AlCl3 is added to 200.0 mL 0.250 M BaCl2, calculate the [Ba2+], [Al3+] and the [...