Given the equation below, determine the number of moles O2 required to completely react with 28 moles of CO.

1. D (24.0 moles CO2)

2. A (.239 moles H2)

Explanation:

1. First Balance the equation

1 C3H8 + 5 O2 ---> 3 CO2 + 4 H2O

Then set up a stoiciometric equation so that the moles of O2 cancel out

40mol O2 x = 24.0 moles CO2

2. Set up a stoichiometric equation

10 grams Fe x x = 0.239 moles H2

14 moles O₂

Explanation:

The equation of the reaction is:

2CO(g)  +  O₂(g)  ⇄  2CO₂(g)    (1)

28 moles

Hence, from equation (1) we have that 2 moles reacts with 1 mol of O₂, so, the number of moles of O₂ required to completely react with 28 moles of CO is:

Therefore, the number of moles of O₂ is 14 moles.  

I hope it helps you!

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )