A 812 g drinking glass is filled with a hot liquid. The liquid transfers 7032 J of energy to the glass. If the temperature of the glass increases by 22 C, what is the specific heat of the glass?

0.3936 J/gC

Explanation:

using the formula: q=mcΔt

q= 7032J

m=812g

ΔT = 22C

plug in and solve:

7032=(812)(c)(22)

c=7032/(812)(22)

c=0.39 J/gC

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