Starting substances An ending substance
Properties:
blue powder
no smell
Properts:
colorless liquid
strong smell
1X
A chemist mixed two substances together, a blue powder with no smell and a coloriess liquid with a strong smell. Their
repeating groups of atoms are shown above on the left. After they were mixed the chemist analyzed the results and
found two substances. One ending substance had the repeating group of atoms shown above on the right.
Is the ending substance the same substance as the blue powder? What happened to the atoms of the starting
substances when the ending substances formed? Be sure to explain your answers to both of these questions

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

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