AH for the reaction IF5 (g) → IF3 (g) + F2 (g)

kJ, give the data below.

IF (8) + F2 (g) → IF3 (8)

IF (g) + 2F2(8) ► F5 (8)

AH=-390 kJ

AH=-745 kJ

A) -1135

B) +35

C) +1135

D) -35

E) +355

Your awser would be a acetone

Molarity is moles of solute over liters of solution. idk if that is what you are talking about, but you can convert moles of solute to grams of solute using dimensional analyzes by using molar mass found on the periodic table.

Hi + naoh -> h2o + nal