Identify the most likely reaction product(s) in the monobromination of 2-pentanone by bromine in the presence of acid in the dark. Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 1-Bromo-2-pentanone and 3-bromo-2-pentanone b 1-Bromo-2-pentanone, 3-bromo-2-pentanone, and 4-bromo-2-pentanone c 1-Bromo-2-pentanone, 3-bromo-2-pentanone, 4-bromo-2-pentanone, and 5-bromo-2-pentanone d 3-Bromo-2-pentanone Your answer e 1-Bromo-2-pentanone

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .