If the natural abundance of ag−107 is 51.84 %, what is the natural abundance of ag−109?

The working equation for this problem is average atomic mass is equal to the summation of the product of relative abundance and mass of isotope. In this problem, just subtract the % abundance of Ag-107 to 100. Thus the % abundance of Ag-109 is 48.16. 

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it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.