Asample of silver (with work function φ = 4.52 ev) is exposed to an ultraviolet light source (λ= 200 nm), which results in the ejection of photoelectrons. what changes will be observed if:

Work function of metal = hc/e h=planck's constant c=speed of light in vacuum = threshold wavelength = 285nm e=1.6 x 10^-19 So = (6.63x10^-34)x (3 x 10^8)/(285x10^-9 x 1.6 x 10^-19) =4.36 eV Maximum energy of emitted electrons = Energy incident - work function = hc/e (where =140nm) =(6.63x10^-34)x (3 x 10^8)/(140x10^-9 x 1.6 x 10^-19) - 4.36 =8.88 - 4.36 = 4.52 eV

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