How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams from 0.0 celsius to 100.0 celsius? (use 4.184 j/g celsius for the specific heat of water.)
type the correct answer to 3 significant digits. if the answer has an exponent, type the number, then ^, then the exponent.

(the question is on the picture.)

In this situation you are meant to use the equation:
Q= cmΔT

Where Q = heat added
C = specific heat
m = mass
ΔT = change of temp. (final temp - initial temp)

for this problem
c = 4.184 J/g°C
m = 46.0 g
ΔT = (100°C - 0°C) = 100°C

So,
Q = 4.18 J/g°C * 46.0 g * 100°C
the units g and °C cancel out. and we're left with
Q = 4.18 J * 46.0 * 100  = 19228 Joules

Non metal is an element or substance that is not a metal metal is a solid material that is typically hard, shiny, malleable, fusible, and ductile, with good electrical and thermal conductivitymetalloid is an element (e.g., germanium or silicon) whose properties are intermediate between those of metals and solid nonmetals. they are electrical semiconductors.