According to the bohr model of the atom, which electron transition would correspond to the shortest wavelength line in the visible emission spectra for hydrogen?

Explanation:

According to Bohr's model, electrons are travelled in defined circular orbit around the nucleus. The orbits of different energy level is labelled by quantum numbers (n). Electrons can jump different energy levels, from higher to lower energy level by releasing energy.

In the visible emission spectrum of hydrogen, there are mainly five series which we are studied in regular. Series are: Lyman series(n=1), Balmer series(n=2), Paschen series(n=3), Bracket series(n=4), Pfund series(n=5).

Wavelength is inversely proportional to the quantum number(n). So, we can conclude that greater the value of n shortest the wavelength. According to above spectral series Pfund series(n=5) have shortest wavelength.

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: