In which compound does chlorine have the highest oxidation number? (1) naclo (3) naclo3(2) naclo2 (4) naclo4

              NaClO₄

Solution:

Let us calculate the oxidation state of Chlorine in each compound one by one;

1) NaClO

               O.N of Na = +1

               O.N of O = -2

So,

               (+1) + (Cl) + (-2) = 0

               1 + Cl - 2 = 0

               Cl = -1 + 2

               Cl = +1

2) NaClO₃

               (+1) + (Cl) + (-2)3 = 0

               (+1) + (Cl) - 6 = 0

               1 + Cl - 6 = 0

               Cl = -1 + 6

               Cl = +5

3) NaClO₂

               (+1) + (Cl) + (-2)2 = 0

               (+1) + (Cl) + (-4) = 0

               1 + Cl - 4 = 0

               Cl = -1 + 4

               Cl = +3

4) NaClO₄

               (+1) + (Cl) + (-2)4 = 0

               (+1) + (Cl) + (-8) = 0

               1 + Cl - 8 = 0

               Cl = -1 + 8

               Cl = +7

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying

what is the question here. i think you messed up.