here we have to get the change of moles on decrease the volume of the reaction in gas phase.
the per the given options it will decrease by (d) 11-50%
we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.
the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total
the moles at equilibrium: 1 - α α α = 1+α
concentrations: 1 - α α α = 1 + α
(concentration = moles/volume, as volume is 1 l)
(where α is the degree of dissociation)
now the dissociation constant in terms of concentration is :
= ![\frac{[so2cl2] x [cl2]}{[so2cl2]}](/tex.php?f=\frac{[so2cl2] x [cl2]}{[so2cl2]})
or, v })
or, =  })
(at v = 1l)
the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total
the moles at equilibrium: 1 - α α α = 1+α
concentrations: (1 - α)/0.5 α/0.5 α/0.5 = (1 + α)/0.5
thus, the dissociation constant in terms of concentration is :
or, 0.5 })
=  0.5})
so, the change of 1 : 1/0.5
or, 1: 2
thus it will decrease by 50%.
or, as per the given options it will decrease by 11-50%
