Write the formulas of the compounds formed by pb4+ with the following anions: cn−, clo3−, so32−, hpo42−

a)

b)

c)

d)

Explanation:

In the given scenario, Pb⁴⁺ is a cation which combines with various anions in order to form a neutral ionic compound. This implies that the charges on the cation and anion must be balanced so that the net charge on the molecule is zero.

a) Pb⁴⁺ with CN⁻

Charge on Pb = +4

Charge on CN = -1

To form a neutral molecule, each Pb⁴⁺ should combine with 4 CN⁻

Formula:

b) Pb⁴⁺ with ClO₃⁻

Charge on Pb = +4

Charge on ClO₃⁻ = -1

To form a neutral molecule, each Pb⁴⁺ should combine with 4 ClO₃⁻

Formula:

c) Pb⁴⁺ with SO₃²⁻

Charge on Pb = +4

Charge on SO₃²⁻ = -2

To form a neutral molecule, each Pb⁴⁺ should combine with 4 ClO₃⁻

Formula:

d) Pb⁴⁺ with HPO₄²⁻

Charge on Pb = +4

Charge on HPO₄²⁻ = -2

To form a neutral molecule, each Pb⁴⁺ should combine with 4 ClO₃⁻

Formula:

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"