Determine the ph of a 0.22 m naf solution at 25°c. the ka of hf is 3.5 × 10-5.

When NaF is in aqueous solution it dissociates into ions and reacts with water forming NaOH and HF. The solution would be a mixture of a strong base and a weak acid. Both of these substances contribute to the pH of the solution. We calculate pH as follows:

Ka + Kb = 1x10^-14
Kb = 1x10^-14 - 3.5x 10 ^-5
Kb = 6.5 x10^-5Kb = [Na+] [OH-] / [NaF]

We let x be the concentration of Na in equilbrium,

Kb = (x) (x) /0.22
6.5 x10^-5 = x^2 /0.22
x = 3.78x10^-3 = [OH]pOH = -log [OH]
pOH = 2.42

pH + pOH = 14
pH = 14 - pOH 
pH = 14 - 2.42 
pH = 11.58

Therefore, the pH of the solution would be 11.58.

If the water vapor content stays the same and the temperature drops, then the relative humidity increases. its vise versa.if the water vapor content stats the same and the temperature rises, the relative humidity decreases. so, yes, i'd say that temperature and humidity have a strong relationship.