A2.0g sample of sx6 (g) has a volume of 329.5 cm3 at 1.00 atm and 20o c. identify the element ‘x’. name the compound.

Volume(v)=329 cm³×10^(-3) litre=0.329 litre
pressure(p)=1 atm
temperature (t)=20°C=(20+273)K=293K
no of moles of gas=n (=m/M)
given mass=m=2 gm
universal gas constant (R)= 0.0821
molar mass(M)=?

Using the case of ideal gas,
pv=nRt
or,1×0.329=(m/M)× 0.0821 ×293
or,0.329=(2/M)× 0.0821 ×293
or,M=(2× 0.0821 ×293)/0.329
M=48.1106/0.329
M=146.23 g
i.e, molar mass of SX6=146 (approx. value)
molar mass of X6=146-molar mass of S
=146-32=114 (approx.)
➡molar mass of X=114/6=19which is the molar mass of fluorine (F).
So,the given compound is SF6

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.

Idon't see the pic?