Chemistry

Chemistry, 30.08.2019 07:30, leannaadrian

Calculate the kinetic energy of an electron ejected by a photon with wavelength 1.57 × 102 nm from a metal with a binding energy of 3.31 ev.

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Physics, 27.06.2019 01:20, taemarie1

Aphoton with energy 662 kev collides with an electron in a metal sample and is scattered causing the electron to recoil. the electron is assumed to be stationary before the collision. write down the relativistic equation of conservation of energy and the equations for the conservation of the horizontal and vertical components of momentum for this collision but do not solve these. (a) a gamma ray photon of wavelength 1.88 pm strikes a metal target and the wavelength of the scattered radiation is measured at an angle (b) 0 90° to the incident beam. calculate: i) the wavelength of the scattered radiation, ii) the kinetic energy of the recoiling electron, ii) the fraction of the energy of the incident photon lost in the collision with the electron, and (iv) the angle made by the trajectory of the recoiling electron with the incident beam. write down an expression for the photon's fractional loss in energy k/e in the type of collision considered in (b) and hence demonstrate with a numerical estimate that the fractional energy loss for visible light is orders of magnitude less than for gamma-ray photons. (n.b., k is kinetic energy, e is total energy)

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Physics, 29.06.2019 23:20, kaylaalvarado2018

Light of 190-nm wavelength shining on a metal ejects electron of maximum kinetic energy 1.462 ev. a. what would be the maximum kinetic energy of electron ejected by light of 232-nm wavelength (in ev, to 3 decimal places) maximum kinetic energy of electron ejected by 232-nm light (ev)- suppose that light of some wavelength λ (< 232 nm) shines on the same metal. using any results, you can glean from (a), give the formula for the negative "stopping potential" for electrons ejected by this light, in ev b. stopping potential-

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Physics, 05.11.2019 01:31, aliopqwas

Acertain minimum energy, , is required to eject an electron from a photosensitive surface. any energy absorbed beyond this minimum gives kinetic energy to the ejected electron. when 510.-nm light falls on a cesium surface, an electron is ejected with a kinetic energy of 8.85×10-20 j. when the wavelength is 430. nm, the kinetic energy is 1.61×10-19 j. a calculate for cesium, in joules.

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