What is the [h3o+] at equilibrium of a 0.50 m weak acid (ha) solution if the ka of the acid is 4.6 × 10−4?

Answer : The concentration of at equilibrium is, 0.015 M

Solution :

The balanced equilibrium reaction will be,

The expression for dissociation constant of weak aciod will be,

where,

= dissociation constant of weak acid

Let the concentration of and be 'x'

Now put all the given values in this expression, we get

The concentration of = = x = 0.015 M

Therefore, the concentration of at equilibrium is, 0.015 M

im pretty sure its b