What mass of carbon dioxide (co2) can be produced from 15.6 g of c6h14 and excess oxygen?

The mass of carbon dioxide produced is 46.7 grams.

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of hexane = 15.6

Molar mass of hexane = 88.2 g/mol

Putting values in equation 1, we get:

The chemical equation for the combustion of hexane follows:

As, oxygen gas is present in excess, it is considered as an excess reagent.

Thus, hexane is considered as a limiting reagent because it limits the formation of product

By Stoichiometry of the reaction:

2 moles of hexane produces 12 moles of carbon dioxide

So, 0.177 moles of hexane will produce = of carbon dioxide

Now, calculating the mass of carbon dioxide by using equation 1:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.062 moles

Putting values in equation 1, we get:

Hence, the mass of carbon dioxide produced is 46.7 grams.

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

the answer to your question is c