Solid barium sulfate dissolves into its respective ions at 25°c. suppose that in a particular solution, [ba2+ ] = 1.76 x 10-3 m. find the value of ksp.

BaSO₄(s) ⇄ Ba²⁺(aq) + SO₄²⁻(aq)

Ksp=[Ba²⁺][SO₄²⁻]

[Ba²⁺]=[SO₄²⁻]

Ksp=[Ba²⁺]²

Ksp=(1.76*10⁻³)² =3.0976×10⁻⁶ ≈3.1×10⁻⁶

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