What is the average kinetic energy of 1 mole of a gas at -32 degrees celsius? (r = 8.314 j/k-mol)
3.006 x 103 j
-3.997 x 102 j
6.010 x 103j
4.321 x 103 j

3.01 x 103 J

Explanation:

To determine the average kinetic energy of a gas, it is necessary to use the equation, KE = 3/2 RT. The value of R, multiplied by the temperature, and multiplied by 3/2, can provide the average kinetic energy of the gas.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml