Ineed ! i will rate
using the equation, c5h12 + 8o2 --> 5co2 + 6h2o, if an excess of pentane (c5h12) were supplied, but only 4 moles of oxygen were available, how many moles of water would be produced?

1 mole

2 moles

3 moles

6 moles
i think it is 3 but i am

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally