Aprotein subunit from an enzyme is part of a research study and needs to be characterized. a total of 0.185 g of this subunit was dissolved in enough water to produce 2.00 ml of solution. at 28 ? c the osmotic pressure produced by the solution was 0.138 atm. what is the molar mass of the protein?

The molar mass of the protein is 16,544 g/mol.

Explanation:

Volume of the solution ,V = 2.00 ml= 0.002 L

Osmotic pressure = 0.138 atm

temperature at which solution is prepared = 28° C = 301 K()

Number of moles of protein,n=

Osmotic pressure is determined by :

The molar mass of the protein is 16,544 g/mol.

The molar mass of the protein : 16517.86 g/mol

Osmosis pressure is the minimum pressure given to the solution so that there is no osmotic displacement from a more dilute solution to a more concentrated solution.

General formula:

π = osmosis pressure (atm)

M = solution concentration (mol / l)

R = constant = 0.08205 L atm mol-1 K-1

T = Temperature (Kelvin)

Mass of a protein: 0.185 g

Volume: 2.00 ml of solution. at 28 C

the osmotic pressure: 0.138 atm

We enter into the equation to find moles from protein concentrations

π = M. R. T

t = 28 C + 273 = 301 K

0.138 = M. 0.08205. 301 K

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idk what the question is about