Aqueous solutions of sodium thiosulfate, na2s2o3, are used as an antidote to some snakebites. how many moles of sodium ions are found in 10.0 ml of a 0.15 m solution of na2s2o3?

When Na2S2O3 dissolves in water, it dissociates into Na+ and S2O32- ions:
Na2S2O3 ⇒2Na+ + S2O32-

So 1 mole of Na2S2O3 generates 2 Na+s.

The moles of Na2S2O3 = volume of Na2S2O3 * molarity of Na2SO3 = 0.01L * 0.15mol/L = 0.0015 mol.

Therefore, the moles of Na+ in the solution = 0.0015mol * 2 = 0.003 mole.

We can't until we know what we are working with or on

Answer is: hydrogen is being oxidized.chemical reaction: co₂ + h₂ → co + h₂o.oxidation half reaction: h₂ → 2h⁺ + 2e⁻.reduction half reaction: c⁺⁴ + 2e⁻ → c⁺².oxidation is increase of oxidation number, hydrogen change oxidation number from neutral charge (in molecule of hydrogen) to oxidation number +1 (in water).