Aqueous hydrochloric acid reacts with solid manganese(iv) oxide to form aqueous manganese(ii) chloride, liquid water and chlorine gas.

The balanced chemical equation for the reaction is

From the question given above, we were told that:

Aqueous hydrochloric acid reacts with solid manganese (iv) oxide to form aqueous manganese(ii) chloride, liquid water and chlorine gas.

The equation for the reaction can be written as follow:

Hydrochloric acid => HCl

Manganese (iv) oxide => MnO₂

Manganese (ii) chloride => MnCl₂

Water => H₂O

Chlorine gas => Cl₂

Hydrochloric acid  + Manganese (iv) oxide —> Manganese (ii) chloride + Water + Chlorine gas

The above equation can be balance as follow:

HCl + MnO₂ → MnCl₂ + H₂O + Cl₂

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:

HCl + MnO₂ → MnCl₂ + 2H₂O + Cl₂

There are 4 atoms of H on the right side and 1 atom on the left side. It can be balance by writing 4 before HCl as shown below:

4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)

Now, the equation is balanced.

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that's just how they are

explanation:

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