What is the molecular formula of a compound containing 89% cesium (cs) and 11% oxygen (o) with a molar mass = 298 g/mol?

The molecular formula will be

Explanation:-

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Cs= 89 g

Mass of O = 11 g

Step 1 : convert given masses into moles.

Moles of Cs =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Cs =

For O =

The ratio of Cs : O= 1:1

Hence the empirical formula is

The empirical weight of = 1(133)+1(16)= 149g.

The molecular weight = 298 g/mole

Now we have to calculate the molecular formula.

The molecular formula will be=

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