You have separate solutions of hcl and h2so4 with the same concentrations in terms of molarity. you wish to neutralize a solution of naoh. which acid solution would require more volume (in ml) to neutralize the base?

The sodium hydroxide under equal concentrations

Explanation:

Hello,

At first, lets consider the neutralization reactions for the involved acids with sodium hydroxide:

As you can see the mole ration between hydrochloric acid and sodium hydroxide is 1 to 1, it means that for equal concentations, the volume of acid will equal the volume of base. However, for sulfuric acid we have a 2 to 1 ratio (2 moles of hydroxide per 1 mole of acid), it means that for equal concentrations, the half of sulfuric acid's volume will be required to neutralize the sodium hydroxide. In such a way, the hydrochloric acid's solution will require more volume to neutralize the sodium hydroxide under equal concentrations.

Best regards.

answer; i believe that the correct answer is (a) potassium(k)