A0.00100 mol sample of ca(oh)2 requires 25.00 ml of aqueous hcl for neutralization according to the reaction below. what is the concentration of the hcl? ca(oh)2(s) + 2hcl(aq) --> cacl2(aq) + h2o(l)

0.08 mol/L is the concentration of the HCl solution.

Explanation:

Moles of calcium = 0.00100 mol

According to reaction ,1 mole of calcium hydroxide reacts with 2 moles of HCl.

Then 0.00100 mole of calcium hydroxide will react with:

Moles of HCl = 0.00200 mol

Volume of solution = 25.00 mL = 0.025 L

Concentration of HCl solution:

50.23 i believe is correct but don't quote me on that.