An element has three naturally occurring isotopes. use the information below to calculate the weighted average atomic mass of the element, showing both the setup and the final answer for the calculation. isotope atomic mass percent abundance i 39.96 u 99.59% ii 37.96 u 0.065% iii 35.97 u 0.336%

In order to calculate an average, we should sum all numbers and divide them by quantity.

Let’s work with qualifications first. Let’s say you got a 10 in 1 exam, then an 8 in 2 exams and a 4 in 2 exams. Your average will be:

= (10*1+8*2+4*2) / 5 = 6.8

If 6 is the minimum, you will pass.

There is another way to calculate this average: applying distributive property.

= 10*1/5+8*2/5+4*2/5 = 6.8

Remember you can convert the fractions into equivalent fractions: 1/5 = 20/100; 2/5 = 40/100

= 10*20/100+8*20/100+4*20/100 = 6.8

We actually don’t have the number of atoms of each mass… we have the percentage instead! So we need to learn this last method for atoms.

Let’s go back to our atoms problem:

99.59% of atoms have a mass of 39.96 u
0.065% of atoms have a mass of 37.96 u
0.336% of atoms have a mass of 35.97 u

So let’s put that in the formula:

Average mass = 39.96u*99.59/100 + 37.96u*0.065/100 + 35.97u*0.336/100

So what you have to know is that a percentage can be converted into a fraction, and you should work that fraction in order to find the average. We can make the calculus shorter putting 100 as the common denominator:

Average mass = (39.96u*99.59 + 37.96u*0.065 + 35.97u*0.336)/100

So actually we are taking the percentage as if it was the quantity, and 100 as if it was the total (the total of all percentages is always 100). Maybe we don’t have 100 atoms, but it will be the same proportion anyway, whatever number we have! And here it is the result:

Average mass = 39,94 u

The gas would begin to expand, and eventually the can would burst or explode.