Determine the molar solubility of pbso4 in pure water. ksp (pbso4 = 1.82 × 10-8.

PbSO4 -> Pb2+ + SO4 2-

So there are 2 different particles. 1 mol of PbSO4 produces 1 mol of Pb2+, and 1 mol of SO4 2- (one of each).

Kps = [Pb2+] [SO4 2-]

We will call “s” the molarity of PbSO4

So the molarity of Pb2+ is also “s” (same number)

And the molarity of SO4 2- is also “s” (same number)

Kps = s*s = s2

1.82 × 10-8 = s2

So, in order to find s, we have to make the square root of 1.82 × 10-8, which is: 0,00013491 M

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

what does the table look like