Calculate the ph of a 0.0075 m ca(oh)2 solution.

Ca(OH)₂ = Ca²⁺ + 2OH⁻

[OH⁻]=2c{Ca(OH)₂}

pH=14+lg[OH⁻]

pH=14+lg(2c{Ca(OH)₂})

pH=14+lg(2*0.0075)=12.18

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