Give the theoretical yield, in moles, of co2 from the reaction of 4.00 moles of c8h18 with 4.00 moles of o2. 2 c8h18(l) + 25 o2(
g. → 16 co2(
g. + 18 h2o(
g.

Theoretical yield = 2.56  moles of CO₂

Explanation:

2 C₈H₁₈(l) + 25 O₂( g) → 16 CO₂( g) + 18 H₈O( g)

As per the given balanced equation 2 moles of C₈H₁₈ combines with 25 moles of O₂. So 4 moles of of C₈H₁₈ requires 50 moles of O₂. But in the given question we have 4 moles of O₂ there O₂ is the limiting reagent.

The limiting reagent determines the yield of the product. Therefore, here O₂ will determines the yield of CO₂.

As per the given balanced equation 25 moles of O₂ yields 16 moles of CO₂.

Therefore, 4 moles of O₂ will yield ( x 4 ) moles of CO₂

= 2.56  moles of CO₂

aluminum

i guess but i think im right

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