Chemistry, 29.11.2019 07:31, shirlsmith72

Which best explains what happens when an electron moves from an excited state to the ground state? the electron absorbs energy as it moves to a lower energy level. the electron absorbs energy as it moves to a higher energy level. the electron releases energy as it moves to a higher energy level. the electron releases energy as it moves to a lower energy level.

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I believe the correct answer would be the last option. When an electrons moves from an excited state to the ground state, it would release energy. An electron in the excited state would mean that it contains high kinetic energy so to move to a lower state some of these energy should be released.

answered: tovarclaudia055

Answer;

The electron releases energy as it moves to a lower energy level.

Explanation;Electrons are sub-atomic particles that occupy energy levels in an atom of any chemical element. These electrons may move from one energy level to another.Electrons may move from a lower energy level or ground state to an excited state or hing energy level, or else move from a higher energy level to a lower energy level.When electron moves from a lower energy level lo a higher energy level energy is absorbed by the atom, and when the movement is from higher energy level to lower energy is released mainly as light.

answered: Guest

6.4 cm (max) - 25 cm (min)

answered: Guest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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