Aball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. ignoring air resistance, how long until the ball hits the ground? use the formula 2003-19-06-00-00_files/i008.jpg, where h is the height of the ball in feet and t is the time in seconds since it is thrown. round your answer to the nearest tenth. a. 2.1 seconds b. 3.8 seconds c. 2.4 seconds d. 1.8 seconds

I think it would be D because it would make more sense.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.