What is the partial pressure of carbon monoxide gas in a sealed vessel that has a total pressure of 2.68 atm and partial pressures of 1.56 atm for oxygen and 0.65 atm for carbon dioxide?

Partial pressure of CO in the sealed vessel is 0.47 atm.

Explanation: From Dalton's law of partial pressures, "Total pressure is the sum of partial pressures of the gases present in the mixture."

So, total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

Let's plug in the values in the formula:

2.68 atm = partial pressure of CO + 1.56 atm + 0.65 atm

2.68 atm = partial pressure of CO + 2.21 atm

partial pressure of CO = 2.68 atm - 2.21 atm

partial pressure of CO = 0.47 atm

Hence, the partial pressure of carbon monoxide gas in a sealed vessel is 0.47 atm.

clouds form

solid ice forms on leaves.

water droplets form on grass.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j