Which substance will most affect the freezing point of water if one mole of the substance is added to one kilogram of water?

pbs

c8h18

na3po4

nacl

Explanation:

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor

= freezing point constant

m= molality =

1. For

, i= 1 as it is a non electrolyte and does not dissociate.

2. For

, i= 1 as it is a non electrolyte and does not dissociate.

3. For

, i= 4 as it is a electrolyte and dissociate to give 4 ions.

4. For

, i= 2 as it is a electrolyte and dissociate to give 2 ions.

Thus as vant hoff factor is highest for and the freezing point will be most affected.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

tracks, burrows, eggshells, nests, tooth marks, or gastroliths